findLastAnyOf
fun CharSequence.findLastAnyOf(strings: Collection<String>, startIndex: Int = lastIndex, ignoreCase: Boolean = false): Pair<Int, String>?(source)
Finds the last occurrence of any of the specified strings in this char sequence, starting from the specified startIndex and optionally ignoring the case.
Since Kotlin
1.0Return
A pair of an index of the last occurrence of matched string from strings and the string matched or null if none of strings are found.
To avoid ambiguous results when strings in strings have characters in common, this method proceeds from the end toward the beginning of this string, and finds at each position the first element in strings that matches this string at that position.
Parameters
startIndex
The index of character to start searching at. The search proceeds backward toward the beginning of the string.
ignoreCase
true to ignore character case when matching a string. By default false.